Home 2nd Year Physics Notes Class 12 Physics Chapter 15 Short Questions and Numerical Notes – Electromagnetic Induction

Class 12 Physics Chapter 15 Short Questions and Numerical Notes – Electromagnetic Induction

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In this post, I am sharing the Class 12 Physics Chapter 15 Short Questions and Numerical Notes PDF for the students of Intermediate Part 2. This chapter’s name is Electromagnetic Induction. Students can download the Class 12 Physics Chapter 15 Short Questions and Numerical Notes PDF on their laptops or mobile. These Physics Notes are for all the boards working under the Punjab Board like Gujranwala Board, Lahore Board, Faisalabad Board, Multan Board, Rawalpindi Board, Sargodha Board, DG Kahn Board, and Sahiwal Board. Here are the complete FSC 2nd Year Physics Notes PDF chapters.

FSC Part 2 Physics Chapter 15 Short Questions and Numerical Notes – Electromagnetic Induction

Class 12 Physics Notes

A light metallic ring is released from above into a vertical bar magnet. Viewed for above, does the current flow clockwise or anticlockwise in the ring?

According to Lenz law, the direction of the induced current is opposite to the cause which produces it, therefore when the metallic ring is released from above into the bar magnet, the magnetic flux is changed in the ring and an induced emf is produced in it and hence North Poole is developed in the ring towards the north pole of the bar magnet. As viewed above, the current flows in a clockwise direction.

Does the induced emf always act to decrease the magnetic flux through a circuit?

No, because according to Lenz’s law “the induced emf is always such as to oppose the cause which produces it” Therefore if magnetic flux increases then induced emf will act in such a way to decrease the magnetic flux, and if magnetic flux decreases then induced emf will act to increase the magnetic flux. So induced emf does not always act to increase the magnetic flux. So induced emf does not always act to decrease the magnetic flux.

When the switch in the circuit is closed, a current is established in the coil and the metal ring jumps upward figure. Why? Describe what would happen to the ring if the battery polarity were reversed?

When the switch in the circuit is closed, the current is set up in the coil. Magnetic flux changes through the metallic ring and an induced emf is produced in it. The face of the ring opposite to the coil develops similar poles of magnet and experiences repulsion from the side of coil and the ring jumps up. If the polarity of the battery is reversed then the ring will jump upward also.

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